180=(x+5)+(x-5)+(x-20)

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Solution for 180=(x+5)+(x-5)+(x-20) equation:



180=(x+5)+(x-5)+(x-20)
We move all terms to the left:
180-((x+5)+(x-5)+(x-20))=0
We calculate terms in parentheses: -((x+5)+(x-5)+(x-20)), so:
(x+5)+(x-5)+(x-20)
We get rid of parentheses
x+x+x+5-5-20
We add all the numbers together, and all the variables
3x-20
Back to the equation:
-(3x-20)
We get rid of parentheses
-3x+20+180=0
We add all the numbers together, and all the variables
-3x+200=0
We move all terms containing x to the left, all other terms to the right
-3x=-200
x=-200/-3
x=66+2/3

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