180=(x-7)(x+4)

Solution for 180=(x-7)(x+4) equation:

180=(x-7)(x+4)

We move all terms to the left:

180-((x-7)(x+4))=0

We multiply parentheses ..

-((+x^2+4x-7x-28))+180=0


We calculate terms in parentheses: -((+x^2+4x-7x-28)), so:

(+x^2+4x-7x-28)

We get rid of parentheses

x^2+4x-7x-28

We add all the numbers together, and all the variables

x^2-3x-28

Back to the equation:

-(x^2-3x-28)


We get rid of parentheses

-x^2+3x+28+180=0

We add all the numbers together, and all the variables

-1x^2+3x+208=0

a = -1; b = 3; c = +208;
Δ = b2-4ac
Δ = 32-4·(-1)·208
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-29}{2*-1}=\frac{-32}{-2}
=+16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+29}{2*-1}=\frac{26}{-2}
=-13
$