180=(z-16)+2z+(z-20)

Solution for 180=(z-16)+2z+(z-20) equation:

180=(z-16)+2z+(z-20)

We move all terms to the left:

180-((z-16)+2z+(z-20))=0


We calculate terms in parentheses: -((z-16)+2z+(z-20)), so:

(z-16)+2z+(z-20)

We add all the numbers together, and all the variables

2z+(z-16)+(z-20)

We get rid of parentheses

2z+z+z-16-20

We add all the numbers together, and all the variables

4z-36

Back to the equation:

-(4z-36)


We get rid of parentheses

-4z+36+180=0

We add all the numbers together, and all the variables

-4z+216=0

We move all terms containing z to the left, all other terms to the right

-4z=-216

z=-216/-4

z=+54