180=10+x+(2/3*x)

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Solution for 180=10+x+(2/3*x) equation: 



180=10+x+(2/3x)

We move all terms to the left:

180-(10+x+(2/3x))=0



Domain of the equation: 3x))!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-(10+x+(+2/3x))+180=0

We multiply all the terms by the denominator


-(10+x+(+2+180*3x))=0



We calculate terms in parentheses: -(10+x+(+2+180*3x)), so:

10+x+(+2+180*3x)

determiningTheFunctionDomain
x+(+2+180*3x)+10

We add all the numbers together, and all the variables

x+(180*3x+2)+10

We get rid of parentheses

x+180*3x+2+10

We add all the numbers together, and all the variables

x+180*3x+12

Wy multiply elements

x+540x+12

We add all the numbers together, and all the variables

541x+12

Back to the equation:

-(541x+12)



We get rid of parentheses

-541x-12=0

We move all terms containing x to the left, all other terms to the right

-541x=12

x=12/-541

x=-12/541

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