180=100+x+(x+12)

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Solution for 180=100+x+(x+12) equation: 



180=100+x+(x+12)

We move all terms to the left:

180-(100+x+(x+12))=0



We calculate terms in parentheses: -(100+x+(x+12)), so:

100+x+(x+12)

determiningTheFunctionDomain
x+(x+12)+100

We get rid of parentheses

x+x+12+100

We add all the numbers together, and all the variables

2x+112

Back to the equation:

-(2x+112)



We get rid of parentheses

-2x-112+180=0

We add all the numbers together, and all the variables

-2x+68=0

We move all terms containing x to the left, all other terms to the right

-2x=-68

x=-68/-2

x=+34

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