180=105+(z-11)+(z-6)

Solution for 180=105+(z-11)+(z-6) equation:

180=105+(z-11)+(z-6)

We move all terms to the left:

180-(105+(z-11)+(z-6))=0


We calculate terms in parentheses: -(105+(z-11)+(z-6)), so:

105+(z-11)+(z-6)

determiningTheFunctionDomain
(z-11)+(z-6)+105

We get rid of parentheses

z+z-11-6+105

We add all the numbers together, and all the variables

2z+88

Back to the equation:

-(2z+88)


We get rid of parentheses

-2z-88+180=0

We add all the numbers together, and all the variables

-2z+92=0

We move all terms containing z to the left, all other terms to the right

-2z=-92

z=-92/-2

z=+46