180=135x2+(45+x)

Solution for 180=135x2+(45+x) equation:

180=135x^2+(45+x)

We move all terms to the left:

180-(135x^2+(45+x))=0

We add all the numbers together, and all the variables

-(135x^2+(x+45))+180=0


We calculate terms in parentheses: -(135x^2+(x+45)), so:

135x^2+(x+45)

We get rid of parentheses

135x^2+x+45

Back to the equation:

-(135x^2+x+45)


We get rid of parentheses

-135x^2-x-45+180=0

We add all the numbers together, and all the variables

-135x^2-1x+135=0

a = -135; b = -1; c = +135;
Δ = b2-4ac
Δ = -12-4·(-135)·135
Δ = 72901
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{72901}}{2*-135}=\frac{1-\sqrt{72901}}{-270}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{72901}}{2*-135}=\frac{1+\sqrt{72901}}{-270}
$