180=36+46x2-3x

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Solution for 180=36+46x2-3x equation:



180=36+46x^2-3x
We move all terms to the left:
180-(36+46x^2-3x)=0
We get rid of parentheses
-46x^2+3x-36+180=0
We add all the numbers together, and all the variables
-46x^2+3x+144=0
a = -46; b = 3; c = +144;
Δ = b2-4ac
Δ = 32-4·(-46)·144
Δ = 26505
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{26505}=\sqrt{9*2945}=\sqrt{9}*\sqrt{2945}=3\sqrt{2945}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3\sqrt{2945}}{2*-46}=\frac{-3-3\sqrt{2945}}{-92} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3\sqrt{2945}}{2*-46}=\frac{-3+3\sqrt{2945}}{-92} $

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