180=3z+(2z+6)+(2z+6)

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Solution for 180=3z+(2z+6)+(2z+6) equation: 



180=3z+(2z+6)+(2z+6)

We move all terms to the left:

180-(3z+(2z+6)+(2z+6))=0



We calculate terms in parentheses: -(3z+(2z+6)+(2z+6)), so:

3z+(2z+6)+(2z+6)

We get rid of parentheses

3z+2z+2z+6+6

We add all the numbers together, and all the variables

7z+12

Back to the equation:

-(7z+12)



We get rid of parentheses

-7z-12+180=0

We add all the numbers together, and all the variables

-7z+168=0

We move all terms containing z to the left, all other terms to the right

-7z=-168

z=-168/-7

z=+24

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