180=40+(10+x)+x

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Solution for 180=40+(10+x)+x equation: 



180=40+(10+x)+x

We move all terms to the left:

180-(40+(10+x)+x)=0

We add all the numbers together, and all the variables

-(40+(x+10)+x)+180=0



We calculate terms in parentheses: -(40+(x+10)+x), so:

40+(x+10)+x

determiningTheFunctionDomain
(x+10)+x+40

We add all the numbers together, and all the variables

x+(x+10)+40

We get rid of parentheses

x+x+10+40

We add all the numbers together, and all the variables

2x+50

Back to the equation:

-(2x+50)



We get rid of parentheses

-2x-50+180=0

We add all the numbers together, and all the variables

-2x+130=0

We move all terms containing x to the left, all other terms to the right

-2x=-130

x=-130/-2

x=+65

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