180=60+(8x+2)+(12x-2)

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Solution for 180=60+(8x+2)+(12x-2) equation: 



180=60+(8x+2)+(12x-2)

We move all terms to the left:

180-(60+(8x+2)+(12x-2))=0



We calculate terms in parentheses: -(60+(8x+2)+(12x-2)), so:

60+(8x+2)+(12x-2)

determiningTheFunctionDomain
(8x+2)+(12x-2)+60

We get rid of parentheses

8x+12x+2-2+60

We add all the numbers together, and all the variables

20x+60

Back to the equation:

-(20x+60)



We get rid of parentheses

-20x-60+180=0

We add all the numbers together, and all the variables

-20x+120=0

We move all terms containing x to the left, all other terms to the right

-20x=-120

x=-120/-20

x=+6

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