180=62+(2x-5)+x

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Solution for 180=62+(2x-5)+x equation: 



180=62+(2x-5)+x

We move all terms to the left:

180-(62+(2x-5)+x)=0



We calculate terms in parentheses: -(62+(2x-5)+x), so:

62+(2x-5)+x

determiningTheFunctionDomain
(2x-5)+x+62

We add all the numbers together, and all the variables

x+(2x-5)+62

We get rid of parentheses

x+2x-5+62

We add all the numbers together, and all the variables

3x+57

Back to the equation:

-(3x+57)



We get rid of parentheses

-3x-57+180=0

We add all the numbers together, and all the variables

-3x+123=0

We move all terms containing x to the left, all other terms to the right

-3x=-123

x=-123/-3

x=+41

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