180=65+(3x-10)+(2x)

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Solution for 180=65+(3x-10)+(2x) equation:



180=65+(3x-10)+(2x)
We move all terms to the left:
180-(65+(3x-10)+(2x))=0
We calculate terms in parentheses: -(65+(3x-10)+2x), so:
65+(3x-10)+2x
determiningTheFunctionDomain (3x-10)+2x+65
We add all the numbers together, and all the variables
2x+(3x-10)+65
We get rid of parentheses
2x+3x-10+65
We add all the numbers together, and all the variables
5x+55
Back to the equation:
-(5x+55)
We get rid of parentheses
-5x-55+180=0
We add all the numbers together, and all the variables
-5x+125=0
We move all terms containing x to the left, all other terms to the right
-5x=-125
x=-125/-5
x=+25

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