180=65+(3x-10)+(2x)

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Solution for 180=65+(3x-10)+(2x) equation: 



180=65+(3x-10)+(2x)

We move all terms to the left:

180-(65+(3x-10)+(2x))=0



We calculate terms in parentheses: -(65+(3x-10)+2x), so:

65+(3x-10)+2x

determiningTheFunctionDomain
(3x-10)+2x+65

We add all the numbers together, and all the variables

2x+(3x-10)+65

We get rid of parentheses

2x+3x-10+65

We add all the numbers together, and all the variables

5x+55

Back to the equation:

-(5x+55)



We get rid of parentheses

-5x-55+180=0

We add all the numbers together, and all the variables

-5x+125=0

We move all terms containing x to the left, all other terms to the right

-5x=-125

x=-125/-5

x=+25

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