180=70+(1+3x)+(-3+5x)

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Solution for 180=70+(1+3x)+(-3+5x) equation: 



180=70+(1+3x)+(-3+5x)

We move all terms to the left:

180-(70+(1+3x)+(-3+5x))=0

We add all the numbers together, and all the variables

-(70+(3x+1)+(5x-3))+180=0



We calculate terms in parentheses: -(70+(3x+1)+(5x-3)), so:

70+(3x+1)+(5x-3)

determiningTheFunctionDomain
(3x+1)+(5x-3)+70

We get rid of parentheses

3x+5x+1-3+70

We add all the numbers together, and all the variables

8x+68

Back to the equation:

-(8x+68)



We get rid of parentheses

-8x-68+180=0

We add all the numbers together, and all the variables

-8x+112=0

We move all terms containing x to the left, all other terms to the right

-8x=-112

x=-112/-8

x=+14

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