180=9/5(k-273.15)+32

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Solution for 180=9/5(k-273.15)+32 equation: 



180=9/5(k-273.15)+32

We move all terms to the left:

180-(9/5(k-273.15)+32)=0



Domain of the equation: 5(k-273.15)+32)!=0

k∈R



We multiply all the terms by the denominator


-(9+180*5(k-273.15)+32)=0



We calculate terms in parentheses: -(9+180*5(k-273.15)+32), so:

9+180*5(k-273.15)+32

determiningTheFunctionDomain
180*5(k-273.15)+9+32

We add all the numbers together, and all the variables

180*5(k-273.15)+41

Wy multiply elements

900k(k+41

Back to the equation:

-(900k(k+41)





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900k(k+41





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900k(k+41





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900k(k+41





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900k(k+41





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900k(k+41





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900k(k+41





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