180=96+2x+(x+12)

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Solution for 180=96+2x+(x+12) equation: 



180=96+2x+(x+12)

We move all terms to the left:

180-(96+2x+(x+12))=0



We calculate terms in parentheses: -(96+2x+(x+12)), so:

96+2x+(x+12)

determiningTheFunctionDomain
2x+(x+12)+96

We get rid of parentheses

2x+x+12+96

We add all the numbers together, and all the variables

3x+108

Back to the equation:

-(3x+108)



We get rid of parentheses

-3x-108+180=0

We add all the numbers together, and all the variables

-3x+72=0

We move all terms containing x to the left, all other terms to the right

-3x=-72

x=-72/-3

x=+24

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