180=x+(2x)+(x+68)

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Solution for 180=x+(2x)+(x+68) equation: 



180=x+(2x)+(x+68)

We move all terms to the left:

180-(x+(2x)+(x+68))=0



We calculate terms in parentheses: -(x+2x+(x+68)), so:

x+2x+(x+68)

We add all the numbers together, and all the variables

3x+(x+68)

We get rid of parentheses

3x+x+68

We add all the numbers together, and all the variables

4x+68

Back to the equation:

-(4x+68)



We get rid of parentheses

-4x-68+180=0

We add all the numbers together, and all the variables

-4x+112=0

We move all terms containing x to the left, all other terms to the right

-4x=-112

x=-112/-4

x=+28

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