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180=x+1/3x
We move all terms to the left:
180-(x+1/3x)=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-(+x+1/3x)+180=0
We get rid of parentheses
-x-1/3x+180=0
We multiply all the terms by the denominator
-x*3x+180*3x-1=0
Wy multiply elements
-3x^2+540x-1=0
a = -3; b = 540; c = -1;
Δ = b2-4ac
Δ = 5402-4·(-3)·(-1)
Δ = 291588
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{291588}=\sqrt{8836*33}=\sqrt{8836}*\sqrt{33}=94\sqrt{33}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(540)-94\sqrt{33}}{2*-3}=\frac{-540-94\sqrt{33}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(540)+94\sqrt{33}}{2*-3}=\frac{-540+94\sqrt{33}}{-6} $
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