180n-360/n=35

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Solution for 180n-360/n=35 equation:


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

180*n-(360/n) = 35 // - 35

180*n-(360/n)-35 = 0

180*n-360*n^-1-35 = 0

180*n^1-360*n^-1-35*n^0 = 0

(180*n^2-35*n^1-360*n^0)/(n^1) = 0 // * n^2

n^1*(180*n^2-35*n^1-360*n^0) = 0

n^1

180*n^2-35*n-360 = 0

180*n^2-35*n-360 = 0

DELTA = (-35)^2-(-360*4*180)

DELTA = 260425

DELTA > 0

n = (260425^(1/2)+35)/(2*180) or n = (35-260425^(1/2))/(2*180)

n = (5*10417^(1/2)+35)/360 or n = (35-5*10417^(1/2))/360

n in { (35-5*10417^(1/2))/360, (5*10417^(1/2)+35)/360}

n in { (35-5*10417^(1/2))/360, (5*10417^(1/2)+35)/360 }

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