18=-2(x-3)-2(3x-2)

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Solution for 18=-2(x-3)-2(3x-2) equation: 



18=-2(x-3)-2(3x-2)

We move all terms to the left:

18-(-2(x-3)-2(3x-2))=0



We calculate terms in parentheses: -(-2(x-3)-2(3x-2)), so:

-2(x-3)-2(3x-2)

We multiply parentheses

-2x-6x+6+4

We add all the numbers together, and all the variables

-8x+10

Back to the equation:

-(-8x+10)



We get rid of parentheses

8x-10+18=0

We add all the numbers together, and all the variables

8x+8=0

We move all terms containing x to the left, all other terms to the right

8x=-8

x=-8/8

x=-1

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