18=-3(2+2n)+4(n+3)

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Solution for 18=-3(2+2n)+4(n+3) equation: 



18=-3(2+2n)+4(n+3)

We move all terms to the left:

18-(-3(2+2n)+4(n+3))=0

We add all the numbers together, and all the variables

-(-3(2n+2)+4(n+3))+18=0



We calculate terms in parentheses: -(-3(2n+2)+4(n+3)), so:

-3(2n+2)+4(n+3)

We multiply parentheses

-6n+4n-6+12

We add all the numbers together, and all the variables

-2n+6

Back to the equation:

-(-2n+6)



We get rid of parentheses

2n-6+18=0

We add all the numbers together, and all the variables

2n+12=0

We move all terms containing n to the left, all other terms to the right

2n=-12

n=-12/2

n=-6

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