18=18+(-16+2F/40+f)

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Solution for 18=18+(-16+2F/40+f) equation: 



18=18+(-16+2/40+F)

We move all terms to the left:

18-(18+(-16+2/40+F))=0



Domain of the equation: 40+F))!=0

We move all terms containing F to the left, all other terms to the right

F))!=-40

F!=-40/1

F!=-40

F∈R



We add all the numbers together, and all the variables

-(18+(F+2/40-16))+18=0

We multiply all the terms by the denominator


-(18+(F+2+18*40-16))=0



We calculate terms in parentheses: -(18+(F+2+18*40-16)), so:

18+(F+2+18*40-16)

determiningTheFunctionDomain
(F+2+18*40-16)+18

We add all the numbers together, and all the variables

(F+706)+18

We get rid of parentheses

F+706+18

We add all the numbers together, and all the variables

F+724

Back to the equation:

-(F+724)



We get rid of parentheses

-F-724=0

We add all the numbers together, and all the variables

-1F-724=0

We move all terms containing F to the left, all other terms to the right

-F=724

F=724/-1

F=-724

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