18=18+(2+3f40+f.)

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Solution for 18=18+(2+3f40+f.) equation: 



18=18+(2+340+F.)

We move all terms to the left:

18-(18+(2+340+F.))=0

We add all the numbers together, and all the variables

-(18+(F.+342))+18=0



We calculate terms in parentheses: -(18+(F.+342)), so:

18+(F.+342)

determiningTheFunctionDomain
(F.+342)+18

We get rid of parentheses

F.+342+18

We add all the numbers together, and all the variables

F.+360

Back to the equation:

-(F.+360)



We get rid of parentheses

-F.-360+18=0

We add all the numbers together, and all the variables

-F.-342=0

We move all terms containing F to the left, all other terms to the right

-F.=342

F=342/1

F=342

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