18=18+(2f-40/44+f)

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Solution for 18=18+(2f-40/44+f) equation: 



18=18+(2f-40/44+f)

We move all terms to the left:

18-(18+(2f-40/44+f))=0



Domain of the equation: 44+f))!=0

We move all terms containing f to the left, all other terms to the right

f))!=-44

f!=-44/1

f!=-44

f∈R



We add all the numbers together, and all the variables

-(18+(+3f-40/44))+18=0

We multiply all the terms by the denominator


-(18+(+3f-40+18*44))=0



We calculate terms in parentheses: -(18+(+3f-40+18*44)), so:

18+(+3f-40+18*44)

determiningTheFunctionDomain
(+3f-40+18*44)+18

We add all the numbers together, and all the variables

(3f+752)+18

We get rid of parentheses

3f+752+18

We add all the numbers together, and all the variables

3f+770

Back to the equation:

-(3f+770)



We get rid of parentheses

-3f-770=0

We move all terms containing f to the left, all other terms to the right

-3f=770

f=770/-3

f=-256+2/3

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