18=18+(40+2f/44+f)

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Solution for 18=18+(40+2f/44+f) equation: 



18=18+(40+2f/44+f)

We move all terms to the left:

18-(18+(40+2f/44+f))=0



Domain of the equation: 44+f))!=0

We move all terms containing f to the left, all other terms to the right

f))!=-44

f!=-44/1

f!=-44

f∈R



We add all the numbers together, and all the variables

-(18+(f+2f/44+40))+18=0

We multiply all the terms by the denominator


-(18+(f+2f+18*44+40))=0



We calculate terms in parentheses: -(18+(f+2f+18*44+40)), so:

18+(f+2f+18*44+40)

determiningTheFunctionDomain
(f+2f+18*44+40)+18

We add all the numbers together, and all the variables

(3f+832)+18

We get rid of parentheses

3f+832+18

We add all the numbers together, and all the variables

3f+850

Back to the equation:

-(3f+850)



We get rid of parentheses

-3f-850=0

We move all terms containing f to the left, all other terms to the right

-3f=850

f=850/-3

f=-283+1/3

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