18=1y+(y+2)+(y+5)

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Solution for 18=1y+(y+2)+(y+5) equation: 



18=1y+(y+2)+(y+5)

We move all terms to the left:

18-(1y+(y+2)+(y+5))=0



We calculate terms in parentheses: -(1y+(y+2)+(y+5)), so:

1y+(y+2)+(y+5)

We add all the numbers together, and all the variables

y+(y+2)+(y+5)

We get rid of parentheses

y+y+y+2+5

We add all the numbers together, and all the variables

3y+7

Back to the equation:

-(3y+7)



We get rid of parentheses

-3y-7+18=0

We add all the numbers together, and all the variables

-3y+11=0

We move all terms containing y to the left, all other terms to the right

-3y=-11

y=-11/-3

y=3+2/3

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