18=2(1+3b)-4(-7+b)

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Solution for 18=2(1+3b)-4(-7+b) equation: 



18=2(1+3b)-4(-7+b)

We move all terms to the left:

18-(2(1+3b)-4(-7+b))=0

We add all the numbers together, and all the variables

-(2(3b+1)-4(b-7))+18=0



We calculate terms in parentheses: -(2(3b+1)-4(b-7)), so:

2(3b+1)-4(b-7)

We multiply parentheses

6b-4b+2+28

We add all the numbers together, and all the variables

2b+30

Back to the equation:

-(2b+30)



We get rid of parentheses

-2b-30+18=0

We add all the numbers together, and all the variables

-2b-12=0

We move all terms containing b to the left, all other terms to the right

-2b=12

b=12/-2

b=-6

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