18=2/5*f

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Solution for 18=2/5*f equation:



18=2/5*f
We move all terms to the left:
18-(2/5*f)=0
Domain of the equation: 5*f)!=0
f!=0/1
f!=0
f∈R
We add all the numbers together, and all the variables
-(+2/5*f)+18=0
We get rid of parentheses
-2/5*f+18=0
We multiply all the terms by the denominator
18*5*f-2=0
Wy multiply elements
90f*f-2=0
Wy multiply elements
90f^2-2=0
a = 90; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·90·(-2)
Δ = 720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{720}=\sqrt{144*5}=\sqrt{144}*\sqrt{5}=12\sqrt{5}$
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{5}}{2*90}=\frac{0-12\sqrt{5}}{180} =-\frac{12\sqrt{5}}{180} =-\frac{\sqrt{5}}{15} $
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{5}}{2*90}=\frac{0+12\sqrt{5}}{180} =\frac{12\sqrt{5}}{180} =\frac{\sqrt{5}}{15} $

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