18=3(c+11)

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Solution for 18=3(c+11) equation: 



18=3(c+11)

We move all terms to the left:

18-(3(c+11))=0



We calculate terms in parentheses: -(3(c+11)), so:

3(c+11)

We multiply parentheses

3c+33

Back to the equation:

-(3c+33)



We get rid of parentheses

-3c-33+18=0

We add all the numbers together, and all the variables

-3c-15=0

We move all terms containing c to the left, all other terms to the right

-3c=15

c=15/-3

c=-5

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