18=3(y-4)+2y

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Solution for 18=3(y-4)+2y equation: 



18=3(y-4)+2y

We move all terms to the left:

18-(3(y-4)+2y)=0



We calculate terms in parentheses: -(3(y-4)+2y), so:

3(y-4)+2y

We add all the numbers together, and all the variables

2y+3(y-4)

We multiply parentheses

2y+3y-12

We add all the numbers together, and all the variables

5y-12

Back to the equation:

-(5y-12)



We get rid of parentheses

-5y+12+18=0

We add all the numbers together, and all the variables

-5y+30=0

We move all terms containing y to the left, all other terms to the right

-5y=-30

y=-30/-5

y=+6

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