18=3(y-4)+3y

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Solution for 18=3(y-4)+3y equation:



18=3(y-4)+3y
We move all terms to the left:
18-(3(y-4)+3y)=0
We calculate terms in parentheses: -(3(y-4)+3y), so:
3(y-4)+3y
We add all the numbers together, and all the variables
3y+3(y-4)
We multiply parentheses
3y+3y-12
We add all the numbers together, and all the variables
6y-12
Back to the equation:
-(6y-12)
We get rid of parentheses
-6y+12+18=0
We add all the numbers together, and all the variables
-6y+30=0
We move all terms containing y to the left, all other terms to the right
-6y=-30
y=-30/-6
y=+5

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