18=4y+2(y+3)

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Solution for 18=4y+2(y+3) equation: 



18=4y+2(y+3)

We move all terms to the left:

18-(4y+2(y+3))=0



We calculate terms in parentheses: -(4y+2(y+3)), so:

4y+2(y+3)

We multiply parentheses

4y+2y+6

We add all the numbers together, and all the variables

6y+6

Back to the equation:

-(6y+6)



We get rid of parentheses

-6y-6+18=0

We add all the numbers together, and all the variables

-6y+12=0

We move all terms containing y to the left, all other terms to the right

-6y=-12

y=-12/-6

y=+2

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