18a2=3

Solution for 18a2=3 equation:

18a^2=3

We move all terms to the left:

18a^2-(3)=0

a = 18; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·18·(-3)
Δ = 216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{216}=\sqrt{36*6}=\sqrt{36}*\sqrt{6}=6\sqrt{6}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{6}}{2*18}=\frac{0-6\sqrt{6}}{36}
=-\frac{6\sqrt{6}}{36}
=-\frac{\sqrt{6}}{6}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{6}}{2*18}=\frac{0+6\sqrt{6}}{36}
=\frac{6\sqrt{6}}{36}
=\frac{\sqrt{6}}{6}
$