18n/(3n-5)=2

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Solution for 18n/(3n-5)=2 equation: 



18n/(3n-5)=2

We move all terms to the left:

18n/(3n-5)-(2)=0



Domain of the equation: (3n-5)!=0

We move all terms containing n to the left, all other terms to the right

3n!=5

n!=5/3

n!=1+2/3

n∈R



We multiply all the terms by the denominator


18n-2*(3n-5)=0

We multiply parentheses

18n-6n+10=0

We add all the numbers together, and all the variables

12n+10=0

We move all terms containing n to the left, all other terms to the right

12n=-10

n=-10/12

n=-5/6

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