18p2-117p+99=0

Solution for 18p2-117p+99=0 equation:

18p^2-117p+99=0

a = 18; b = -117; c = +99;
Δ = b2-4ac
Δ = -1172-4·18·99
Δ = 6561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6561}=81$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-117)-81}{2*18}=\frac{36}{36}
=1
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-117)+81}{2*18}=\frac{198}{36}
=5+1/2
$