18r-3(2r-5)=6(3r-9)-9r

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Solution for 18r-3(2r-5)=6(3r-9)-9r equation: 



18r-3(2r-5)=6(3r-9)-9r

We move all terms to the left:

18r-3(2r-5)-(6(3r-9)-9r)=0

We multiply parentheses

18r-6r-(6(3r-9)-9r)+15=0



We calculate terms in parentheses: -(6(3r-9)-9r), so:

6(3r-9)-9r

We add all the numbers together, and all the variables

-9r+6(3r-9)

We multiply parentheses

-9r+18r-54

We add all the numbers together, and all the variables

9r-54

Back to the equation:

-(9r-54)



We add all the numbers together, and all the variables

12r-(9r-54)+15=0

We get rid of parentheses

12r-9r+54+15=0

We add all the numbers together, and all the variables

3r+69=0

We move all terms containing r to the left, all other terms to the right

3r=-69

r=-69/3

r=-23

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