18r-3(2r-5)=6(3r-9)-9r

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Solution for 18r-3(2r-5)=6(3r-9)-9r equation:



18r-3(2r-5)=6(3r-9)-9r
We move all terms to the left:
18r-3(2r-5)-(6(3r-9)-9r)=0
We multiply parentheses
18r-6r-(6(3r-9)-9r)+15=0
We calculate terms in parentheses: -(6(3r-9)-9r), so:
6(3r-9)-9r
We add all the numbers together, and all the variables
-9r+6(3r-9)
We multiply parentheses
-9r+18r-54
We add all the numbers together, and all the variables
9r-54
Back to the equation:
-(9r-54)
We add all the numbers together, and all the variables
12r-(9r-54)+15=0
We get rid of parentheses
12r-9r+54+15=0
We add all the numbers together, and all the variables
3r+69=0
We move all terms containing r to the left, all other terms to the right
3r=-69
r=-69/3
r=-23

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