18r2+61r=50

Solution for 18r2+61r=50 equation:

18r^2+61r=50

We move all terms to the left:

18r^2+61r-(50)=0

a = 18; b = 61; c = -50;
Δ = b2-4ac
Δ = 612-4·18·(-50)
Δ = 7321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(61)-\sqrt{7321}}{2*18}=\frac{-61-\sqrt{7321}}{36}
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(61)+\sqrt{7321}}{2*18}=\frac{-61+\sqrt{7321}}{36}
$