18t+4(t+5)=48

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Solution for 18t+4(t+5)=48 equation: 



18t+4(t+5)=48

We move all terms to the left:

18t+4(t+5)-(48)=0

We multiply parentheses

18t+4t+20-48=0

We add all the numbers together, and all the variables

22t-28=0

We move all terms containing t to the left, all other terms to the right

22t=28

t=28/22

t=1+3/11

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