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18x(-2x-4)+12=-52
We move all terms to the left:
18x(-2x-4)+12-(-52)=0
We add all the numbers together, and all the variables
18x(-2x-4)+64=0
We multiply parentheses
-36x^2-72x+64=0
a = -36; b = -72; c = +64;
Δ = b2-4ac
Δ = -722-4·(-36)·64
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{14400}=120$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-120}{2*-36}=\frac{-48}{-72} =2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+120}{2*-36}=\frac{192}{-72} =-2+2/3 $
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