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18x(2x=4)
We move all terms to the left:
18x(2x-(4))=0
We multiply parentheses
36x^2-72x=0
a = 36; b = -72; c = 0;
Δ = b2-4ac
Δ = -722-4·36·0
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5184}=72$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-72}{2*36}=\frac{0}{72} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+72}{2*36}=\frac{144}{72} =2 $
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