18x+4=10x2

Solution for 18x+4=10x2 equation:

18x+4=10x^2

We move all terms to the left:

18x+4-(10x^2)=0

determiningTheFunctionDomain
-10x^2+18x+4=0

a = -10; b = 18; c = +4;
Δ = b2-4ac
Δ = 182-4·(-10)·4
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-22}{2*-10}=\frac{-40}{-20}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+22}{2*-10}=\frac{4}{-20}
=-1/5
$