18x+j1/2=6(3x+25)

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Solution for 18x+j1/2=6(3x+25) equation: 


x in (-oo:+oo)

(j^1)/2+18*x = 6*(3*x+25) // - 6*(3*x+25)

(j^1)/2-(6*(3*x+25))+18*x = 0

j/2-6*(3*x+25)+18*x = 0

(-6*2*(3*x+25))/2+j/2+(2*18*x)/2 = 0

j-6*2*(3*x+25)+2*18*x = 0

j-36*x+36*x-300 = 0

j-300 = 0

(j-300)/2 = 0

(j-300)/2 = 0 // * 2

j-300 = 0

x belongs to the empty set

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