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18x-4-12x=2(3x-3)+2
We move all terms to the left:
18x-4-12x-(2(3x-3)+2)=0
We add all the numbers together, and all the variables
6x-(2(3x-3)+2)-4=0
We calculate terms in parentheses: -(2(3x-3)+2), so:We get rid of parentheses
2(3x-3)+2
We multiply parentheses
6x-6+2
We add all the numbers together, and all the variables
6x-4
Back to the equation:
-(6x-4)
6x-6x+4-4=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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