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18x^2+114x-84=0
a = 18; b = 114; c = -84;
Δ = b2-4ac
Δ = 1142-4·18·(-84)
Δ = 19044
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{19044}=138$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(114)-138}{2*18}=\frac{-252}{36} =-7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(114)+138}{2*18}=\frac{24}{36} =2/3 $
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