18x2+12x-15=0

Solution for 18x2+12x-15=0 equation:

18x^2+12x-15=0

a = 18; b = 12; c = -15;
Δ = b2-4ac
Δ = 122-4·18·(-15)
Δ = 1224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1224}=\sqrt{36*34}=\sqrt{36}*\sqrt{34}=6\sqrt{34}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-6\sqrt{34}}{2*18}=\frac{-12-6\sqrt{34}}{36}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+6\sqrt{34}}{2*18}=\frac{-12+6\sqrt{34}}{36}
$