18x2+17x-17=0

Solution for 18x2+17x-17=0 equation:

18x^2+17x-17=0

a = 18; b = 17; c = -17;
Δ = b2-4ac
Δ = 172-4·18·(-17)
Δ = 1513
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{1513}}{2*18}=\frac{-17-\sqrt{1513}}{36}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{1513}}{2*18}=\frac{-17+\sqrt{1513}}{36}
$