18x2+18=39x

Solution for 18x2+18=39x equation:

18x^2+18=39x

We move all terms to the left:

18x^2+18-(39x)=0

a = 18; b = -39; c = +18;
Δ = b2-4ac
Δ = -392-4·18·18
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-39)-15}{2*18}=\frac{24}{36}
=2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-39)+15}{2*18}=\frac{54}{36}
=1+1/2
$