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18x^2+54x+36=0
a = 18; b = 54; c = +36;
Δ = b2-4ac
Δ = 542-4·18·36
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-18}{2*18}=\frac{-72}{36} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+18}{2*18}=\frac{-36}{36} =-1 $
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