18x2+63x+55=0

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Solution for 18x2+63x+55=0 equation:



18x^2+63x+55=0
a = 18; b = 63; c = +55;
Δ = b2-4ac
Δ = 632-4·18·55
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-3}{2*18}=\frac{-66}{36} =-1+5/6 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+3}{2*18}=\frac{-60}{36} =-1+2/3 $

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