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18x^2+75x+42x=0
We add all the numbers together, and all the variables
18x^2+117x=0
a = 18; b = 117; c = 0;
Δ = b2-4ac
Δ = 1172-4·18·0
Δ = 13689
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{13689}=117$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(117)-117}{2*18}=\frac{-234}{36} =-6+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(117)+117}{2*18}=\frac{0}{36} =0 $
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